Last updated at May 29, 2018 by Teachoo

Transcript

Ex 5.3 ,20 In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato and other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line. A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run? [Hint : To pick up the first potato and the second potato, the total distance (in metres) run by a competitor is 2 × 5 + 2 × (5 + 3)] Distance run to pick first potato = 5 m each side = 5 m ×2 = 10 m both side Distance run to pick second potato = 5 + 3 m each side = 8 m each side = 16 m both sides Distance run to pick third potato = 8 + 3 m each side = 11 m each side = 22 m both side Hence the series is 10, 16, 22, ……. Since difference is same, it is an AP Now, we need to calculate total distance she runs to pick 10 potatoes i.e. S10 We can use the formula Sn = 𝑛/2 (2𝑎+(𝑛−1)𝑑) Here, n = 10 & a = 10, d = 6 Putting the values in formula Sn = 𝑛/2 (2𝑎+(𝑛−1)𝑑) = 10/2(2×10+(10−1)×6) = 5 (20+9×6) = 5(20+54) = 5 ×74 = 370 Hence, Total distance covered = 370 m

Chapter 5 Class 10 Arithmetic Progressions

Class 10

Important Questions for Exam - Class 10

- Chapter 1 Class 10 Real Numbers
- Chapter 2 Class 10 Polynomials
- Chapter 3 Class 10 Pair of Linear Equations in Two Variables
- Chapter 4 Class 10 Quadratic Equations
- Chapter 5 Class 10 Arithmetic Progressions
- Chapter 6 Class 10 Triangles
- Chapter 7 Class 10 Coordinate Geometry
- Chapter 8 Class 10 Introduction to Trignometry
- Chapter 9 Class 10 Some Applications of Trignometry
- Chapter 10 Class 10 Circles
- Chapter 11 Class 10 Constructions
- Chapter 12 Class 10 Areas related to Circles
- Chapter 13 Class 10 Surface Areas and Volumes
- Chapter 14 Class 10 Statistics
- Chapter 15 Class 10 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.