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Ex 5.1, 3 - For the A.P.s, write first term and common - Ex 5.1

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Ex 5.1, 3 - Chapter 5 Class 10 Arithmetic Progressions - Part 2

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Ex 5.1, 3 - Chapter 5 Class 10 Arithmetic Progressions - Part 3 Ex 5.1, 3 - Chapter 5 Class 10 Arithmetic Progressions - Part 4

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Ex 5.1, 3 - Chapter 5 Class 10 Arithmetic Progressions - Part 5

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Ex 5.1, 3 For the following A.P.s, write the first term and the common difference. (i) 3, 1, −1, −3 … 3, 1, –1, –3… First term = a = 3 Common difference = d = Difference between 2 consecutive terms = Second term – First Term = 1 – 3 = –2 Hence , a = 3 , d = –2 Ex 5.1, 3 For the following A.P.s, write the first term & the common difference. (ii) − 5, −1, 3, 7 … –5, –1, 3, 7,… First term = –5 Common difference = d = Difference between second and first term = –1 – (–5) = –1 + 5 = 4 Hence, a = –5 & d = 4 Ex 5.1, 3 For the following A.P.s, write the first term & the common difference. (iii) 1/3, 5/3, 9/3 , 13/3 1/3 , 5/3 , 9/3 , 13/3 First term of AP = a = 𝟏/𝟑 Common difference = d = Difference of second and first term = 5/3 – 1/3 = (5 − 1)/3 = 𝟒/𝟑 Hence, a = 𝟏/𝟑 , d = 𝟒/𝟑 Ex 5.1, 3 For the following A.P.s, write the first term &the common difference. (iv) 0.6, 1.7, 2.8, 3.9 … 0.6, 1.7, 2.8, 3.9,… First term of AP = a = 0.6 Common difference = d = Difference of 2 consecutive terms = Difference of second and first term = 1.7 – 0.6 = 1.1 Hence, a = 0.6 & d = 1.1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.