Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 11.3
Ex 11.3, 2 (a)
Ex 11.3, 2 (b) Important
Ex 11.3, 2 (c)
Ex 11.3, 2 (d) Important
Ex 11.3, 3 (i)
Ex 11.3, 3 (ii) Important
Ex 11.3, 3 (iii) Important
Ex 11.3, 3 (iv)
Ex 11.3, 3 (v) Important
Ex 11.3, 3 (vi)
Ex 11.3, 4 (a) Important
Ex 11.3, 4 (b)
Ex 11.3, 4 (c) Important
Ex 11.3, 4 (d)
Ex 11.3, 4 (e) Important
Ex 11.3, 4 (f)
Ex 11.3, 4 (g) Important
Ex 11.3, 4 (h) Important You are here
Ex 11.3, 4 (i)
Ex 11.3, 4 (j) Important
Last updated at July 5, 2023 by Teachoo
Ex 11.3, 4 Express the number appearing in the following statements in standard form. (h) 60,230,000,000,000,000,000,000 molecules are contained in a drop of water weighing 1.8 gm 60,230,000,000,000,000,000,000 = 6023 × 〖10〗^19 = (6.023 × 103) × 〖10〗^19 = 6.023 × 〖10〗^3 × 〖10〗^19 = 6.023 × 〖10〗^(3 + 19) = 6.023 × 〖10〗^22 Answer is 6.023 × 〖𝟏𝟎〗^𝟐𝟐 molecules (Using am × an = am + n)