Prove that root โˆš5 is irrational (with Video) - Teachoo - Ex 1.2 - Ex 1.2

part 2 - Ex 1.2, 1 - Ex 1.2 - Serial order wise - Chapter 1 Class 10 Real Numbers
part 3 - Ex 1.2, 1 - Ex 1.2 - Serial order wise - Chapter 1 Class 10 Real Numbers part 4 - Ex 1.2, 1 - Ex 1.2 - Serial order wise - Chapter 1 Class 10 Real Numbers

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Transcript

Ex 1.2, 1 Prove that โˆš5 is irrational. We have to prove โˆš5 is irrational Let us assume the opposite, i.e., โˆš5 is rational Hence, โˆš5 can be written in the form ๐‘Ž/๐‘ where a and b (bโ‰  0) are co-prime (no common factor other than 1) Hence, โˆš๐Ÿ“ = ๐’‚/๐’ƒ โˆš5 b = a Squaring both sides (โˆš5b)2 = a2 5b2 = a2 ๐’‚^๐Ÿ/๐Ÿ“ = b2 Hence, 5 divides a2 So, 5 shall divide a also Hence, we can say ๐‘Ž/5 = c where c is some integer So, a = 5c Now we know that 5b2 = a2 Putting a = 3c 5b2 = (5c)2 5b2 = 25c2 b2 = 1/5 ร— 25c2 b2 = 5c2 ๐’ƒ^๐Ÿ/๐Ÿ“ = c2 Hence, 5 divides b2 So, 5 divides b also By (1) and (2) 5 divides both a & b Hence 5 is a factor of a and b So, a & b have a factor 5 Therefore, a & b are not co-prime. Hence, our assumption is wrong โˆด By contradiction, โˆš๐Ÿ“ is irrational

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