Ex 15.1, 6 - A teacher wanted to analyse the performance - Ex 15.1 Ex  15.1, 6 - Chapter 15 Class 9 Probability - Part 2

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Transcript

Ex15.1, 6 A teacher wanted to analyse the performance of two sections of students in a mathematics test of 100 marks. Looking at their performances, she found that a few students got under 20 marks and a few got 70 marks or above. So she decided to group them into intervals of varying sizes as follows: 0 โˆ’ 20, 20 โˆ’ 30โ€ฆ 60 โˆ’ 70, 70 โˆ’ 100. Then she formed the following table: (i) Find the probability that a student obtained less than 20% in the mathematics test. Total number of students = 90 Students with less than 20% marks = Students who have 0 โ€“ 20 marks = 7 Probability that a student obtained less than 20% = (๐‘†๐‘ก๐‘ข๐‘‘๐‘’๐‘›๐‘ก๐‘  ๐‘คโ„Ž๐‘œ ๐‘œ๐‘๐‘ก๐‘Ž๐‘–๐‘›๐‘’๐‘‘ ๐‘™๐‘’๐‘ ๐‘  ๐‘กโ„Ž๐‘Ž๐‘› 20% ๐‘š๐‘Ž๐‘Ÿ๐‘˜๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘ก๐‘ข๐‘‘๐‘’๐‘›๐‘ก๐‘ ) = 7/90 Ex15.1, 6 (ii) Find the probability that a student obtained marks 60 or above. Total number of students = 90 Students who have 60 marks or above = Students who have 60 โ€“ 70 marks + Students who have 70 โ€“ above marks = 15 + 8 = 23 Probability that a student obtained marks 60 or above. = (๐‘†๐‘ก๐‘ข๐‘‘๐‘’๐‘›๐‘ก๐‘  ๐‘คโ„Ž๐‘œ ๐‘œ๐‘๐‘ก๐‘Ž๐‘–๐‘›๐‘’๐‘‘ 60 ๐‘š๐‘Ž๐‘Ÿ๐‘˜๐‘  ๐‘œ๐‘Ÿ ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘ก๐‘ข๐‘‘๐‘’๐‘›๐‘ก๐‘ ) = 23/90

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo