Question 12 - Questions - Basic Probability - Probability

Last updated at April 16, 2024 by

Ex 15.1, 12 - The frequency distribution table represents - Grouped frequency

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Question 12 The above frequency distribution table represents the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 0.16 on any of these days. Total number of days = 30 Number days for which the concentration of sulphur dioxide was in the interval of 0.12 0.16 = 2 P(concentration of sulphur dioxide as in interval 0.12 0.16) = ( 0.12 0.16)/( ) = 2/30 = 1/15

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.