Question 1 5 (h) - Chapter 1 Class 7 Integers

Last updated at August 14, 2026 by

Ex 1.3, 5 - Chapter 1 Class 7 Integers - Part 8

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Ex 1.2, 5 Find the product, using suitable properties: (h) (–57) × (–19) + 57 (−57) × (−19) + 57 = 57 × 19 + 57 Taking 57 common = 57 × (19 + 1) = 57 × 20 = 57 × 2 × 10 = 114 × 10 = 1140

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