Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 1.2
Ex 1.2, 2 (a) Important
Ex 1.2, 2 (b)
Ex 1.2, 3 (i)
Ex 1.2, 3 (ii) Important
Ex 1.2, 4
Question 1 5 (a) Deleted for CBSE Board 2024 Exams
Question 1 5 (b) Important Deleted for CBSE Board 2024 Exams
Question 1 5 (c) Deleted for CBSE Board 2024 Exams
Question 1 5 (d) Important Deleted for CBSE Board 2024 Exams
Question 1 5 (e) Important Deleted for CBSE Board 2024 Exams You are here
Question 1 5 (f) Deleted for CBSE Board 2024 Exams
Question 1 5 (g) Important Deleted for CBSE Board 2024 Exams
Question 1 5 (h) Deleted for CBSE Board 2024 Exams
Question 2 Deleted for CBSE Board 2024 Exams
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Last updated at May 29, 2023 by Teachoo
Ex 1.2, 5 Find the product, using suitable properties: (e) 625 × (–35) + (– 625) × 65 625 × (–35) + (– 625) × 65 = 625 × (-35) + 625 × (−65) Taking 625 common = 625 × [(−35) + (−65)] = 625 × [−35 − 65] = 625 × −[35 + 65] = 625 × −100 = −62500