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Question 1 5 (h) - Chapter 1 Class 7 Integers

Last updated at May 29, 2023 by

Ex 1.3, 5 - Chapter 1 Class 7 Integers - Part 8

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Ex 1.2, 5 Find the product, using suitable properties: (h) (–57) × (–19) + 57 (−57) × (−19) + 57 = 57 × 19 + 57 Taking 57 common = 57 × (19 + 1) = 57 × 20 = 57 × 2 × 10 = 114 × 10 = 1140

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.