Question 1 5 (e) - Chapter 1 Class 7 Integers

Last updated at Dec. 16, 2024 by

Ex 1.3, 5 - Chapter 1 Class 7 Integers - Part 5

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Ex 1.2, 5 Find the product, using suitable properties: (e) 625 × (–35) + (– 625) × 65 625 × (–35) + (– 625) × 65 = 625 × (-35) + 625 × (−65) Taking 625 common = 625 × [(−35) + (−65)] = 625 × [−35 − 65] = 625 × −[35 + 65] = 625 × −100 = −62500

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo