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Ex 13.8, 2 (ii) - Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
Last updated at Aug. 26, 2021 by Teachoo
Chapter 13 Class 9 Surface Areas and Volumes
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Transcript
Ex 13.8, 2 Find the amount of water displaced by a solid spherical ball of diameter (ii) 0.21 m Amount of water displaced by sphere is its volume Radius of sphere = r = /2 = (0.21/2) m = 0.105 m Amount of water displaced = Volume of sphere = 4/3 r3 = 4/3 22/7 0.105 0.105 0.105 = 4/3 22/7 105/1000 105/1000 105/1000 = 4 22 5/1000 105/1000 105/1000 = 0.004851 m3
