1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise
  3. Ex 13.8

Ex 13.8, 2 (i) - Chapter 13 Class 9 Surface Areas and Volumes (Term 2)

Last updated at Aug. 26, 2021 by

Ex 13.8, 2 - Find amount of water displaced by a solid - Ex 13.8

 

 

  1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise

    3. Ex 13.8

    Examples →

Transcript

Ex 13.8 , 2 Find the amount of water displaced by a solid spherical ball of diameter 28 cm Amount of water displaced by sphere is its volume Radius of sphere = r = /2 = (28/2) cm = 14 cm Amount of water displaced = Volume of sphere = 4/3 r3 = 4/3 22/7 14 14 14 cm3 = 34496/3 cm3 = 11498.66 cm3

Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.