1. Chapter 13 Class 9 Surface Areas and Volumes
  2. Serial order wise
  3. Ex 13.8

Ex 13.8, 2 - Class 9

Last updated at Dec. 8, 2016 by

Ex 13.8, 2 - Find amount of water displaced by a solid - Ex 13.8

  1. Chapter 13 Class 9 Surface Areas and Volumes
  2. Serial order wise
    3. Ex 13.8
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Ex 13.8 , 2 Find the amount of water displaced by a solid spherical ball of diameter 28 cm Amount of water displaced by sphere is its volume Radius of sphere = r = ๐ท๐‘–๐‘Ž๐‘š๐‘’๐‘ก๐‘’๐‘Ÿ/2 = (28/2) cm = 14 cm Amount of water displaced = Volume of sphere = 4/3 ฯ€r3 = 4/3 ร—22/7 ร—14ร—14ร—14 cm3 = 34496/3 cm3 = 11498.66 cm3 Ex 13.8, 2 Find the amount of water displaced by a solid spherical ball of diameter (ii) 0.21 m Amount of water displaced by sphere is its volume Radius of sphere = r = ๐ท๐‘–๐‘Ž๐‘š๐‘’๐‘ก๐‘’๐‘Ÿ/2 = (0.21/2) m = 0.105 m Amount of water displaced = Volume of sphere = 4/3 ฯ€r3 = 4/3 ร—22/7 ร—0.105ร—0.105ร—0.105 = 4/3 ร—22/7 ร—105/1000ร—105/1000ร—105/1000 = 4 ร—22 ร—5/1000ร—105/1000ร—105/1000 = 0.004851 m3

Chapter 13 Class 9 Surface Areas and Volumes
Serial order wise

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