Ex 13.7, 2 - Chapter 13 Class 9 Surface Areas and Volumes - Part 3

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Ex 13.7, 2 - Chapter 13 Class 9 Surface Areas and Volumes - Part 4

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  1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise

Transcript

Ex 13.7, 2 Assume π = 22/7 , unless stated otherwise. Find the capacity in litres of a conical vessel with (ii) height 12 cm, slant height 13 cm Given height of cone = h = 12 cm Slant height = l = 13 cm Let radius of cone = r cm We know that l2 = h2 + r2 132 = 122 + r2 132 – 122 = r2 r2 = 132 – 122 r2 = 169 – 144 r2 = 25 r = √("25" ) r = √(5^2 ) = 5 cm Capacity = Volume of cone = 1/3πr2h = 1/3 × 22/7 × 5 × 5 × 12 cm3 = 1× 22/7 × 5 × 5 × 4 cm3 = 2200/7 cm3. = 2200/7 × 1/1000 litres = 11/35 litres

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.