Ex 13.7, 7 - A right triangle ABC with sides 5 cm, 12 cm - Volume Of Cone

  1. Chapter 13 Class 9 Surface Areas and Volumes
  2. Serial order wise
Ask Download

Transcript

Ex 13.7 , 7 A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained. Let ABC with right angle at B. AC will be hypotenuse, AC = 13 cm And AB = 12 cm, BC = 5 cm We revolve ∆ ABC about the side AB (= 12 cm) , we get a cone as shown in the figure. Radius = r = 5 cm, & Height = h = 12 cm Volume of solid so obtained = 1/3 πr2h = (1/3×"π" ×5×5×12) cm3 = (1×"π" ×25×4) cm3 = 100 π cm3 .

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.