1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise
  3. Ex 13.7

Ex 13.7, 1 (ii) - Chapter 13 Class 9 Surface Areas and Volumes (Term 2)

Last updated at Aug. 26, 2021 by

Ex 13.7, 1 - Chapter 13 Class 9 Surface Areas and Volumes - Part 2

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  1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise

    3. Ex 13.7

    Ex 13.8 →

Transcript

Ex 13.7 , 1 Assume = 22/7 , unless stated otherwise. Find the volume of the right circular cone with (ii) radius 3.5 cm, height 12 cm Here, r = 3.5 cm and h = 12 cm Volume of the cone = 1/3 r2h = 1/3 22/7 3.5 3.5 12 cm3 = 1 22/7 35/10 35/10 4 cm3 = 1 22 5/10 35/10 4 cm3 = 154 cm3

Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
Serial order wise

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.