If the perimeter of a circle is equal to that of a square, then the ratio of their areas is

(A) 22 : 7 Ā 

(B) 14 : 11 Ā 

(C) 7 : 22 Ā 

(D) 11: 14

If the perimeter of a circle is equal to that of a square (MCQ) - NCERT Exemplar - MCQ

part 2 - Question 7 - NCERT Exemplar - MCQ - Serial order wise - Chapter 11 Class 10 Areas related to Circles
part 3 - Question 7 - NCERT Exemplar - MCQ - Serial order wise - Chapter 11 Class 10 Areas related to Circles part 4 - Question 7 - NCERT Exemplar - MCQ - Serial order wise - Chapter 11 Class 10 Areas related to Circles

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Transcript

Question 7 If the perimeter of a circle is equal to that of a square, then the ratio of their areas is (A) 22 : 7 (B) 14 : 11 (C) 7 : 22 (D) 11: 14 Let Radius of circle = r Side of square = a Now, given that Circumference of Circle = Perimeter of Square 2šœ‹r = 4a šœ‹r = 2a 2a = šœ‹r a = š…/šŸ š’“ Now, we need to find ratio between Area of square and circle Circle Area of circle = š…š’“^šŸ Square Area of square = a2 = (šœ‹/2 š‘Ÿ)^2 = š…^šŸ/šŸ’ š’“^šŸ Now, (š‘Øš’“š’†š’‚ š’š’‡ š’„š’Šš’“š’„š’š’†)/(š‘Øš’“š’†š’‚ š’š’‡ š’”š’’š’–š’‚š’“š’†)=(šœ‹š’“^šŸ)/((šœ‹^šŸ š’“^šŸ)/šŸ’) =šœ‹š‘Ÿ^2 Ɨ4/(šœ‹^2 š‘Ÿ^2 ) =4/(šœ‹ ) =4/(22/7) =(4 Ɨ 7)/22 =(2 Ɨ 7)/11 =šŸšŸ’/šŸšŸ ∓ Required ratio is 14 : 11 So, the correct answer is (B) =4/(22/7) =(4 Ɨ 7)/22 =(2 Ɨ 7)/11 =šŸšŸ’/šŸšŸ ∓ Required ratio is 14 : 11 So, the correct answer is (B) =4/(22/7) =(4 Ɨ 7)/22 =(2 Ɨ 7)/11 =šŸšŸ’/šŸšŸ ∓ Required ratio is 14 : 11 So, the correct answer is (B)

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