Case Based Questions (MCQ)

Chapter 8 Class 10 Introduction to Trignometry
Serial order wise

This question is inspired from Ex 9.1, 1 - Chapter 9 Class 10 - Applications of Trigonometry

## (c) CircleΒ  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β (d) Mensuration

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### Transcript

Question A circus artist is climbing from the ground along a rope stretched from the top of a vertical pole and tied at the ground. The height of the pole is 12 m and the angle made by the rope with ground level is 30Β°. Give answer to the following questionsQuestion 1 The distance covered by the artist in climbing the top of the pole is: (a) 24 m (b) 36 m (c) 28 m (d) 22 m We need to find AC In Ξ ABC sin C = π΄π΅/π΄πΆ sin 30Β° = 12/π΄πΆ 1/2 = 12/π΄πΆ AC = 2 Γ 12 AC = 24 m So, the correct answer is (A) Question 2 The length of BC is: (a) 24β3 m (b) 12β3 m (c) 2β3 m (d) β3 m In Ξ ABC tan C = π΄π΅/π΅πΆ tan 30Β° = 12/π΅πΆ 1/β3 = 12/π΅πΆ BC = 12 Γ β3 BC = 12β3 m So, the correct answer is (B) Question 3 If sinβ‘γ(π΄+π΅)γ=β3/2 , then the value of (A + B) is: (a) 30Β° (b) 90Β° (c) 60Β° (d) 45Β° Given, sinβ‘γ(π΄+π΅)γ=β3/2 sinβ‘γ(π΄+π΅)γ=sinβ‘γ60Β° γ Comparing angles A + B = 60Β° So, the correct answer is (C) Question 4 In Ξ ABC, given that β  A = 60Β° and β  C = 30Β°, then value of sin A cos C + cos C sin A is (a) 0 (b) β (c) 10 (d) 3/2Now, sin A cos C + cos C sin A = 2 Γ sin A cos C = 2 Γ sin 60Β° cos 30Β° = 2 Γ β3/2 Γ β3/2 = 2 Γ 3/4 = π/π So, the correct answer is (B) Question 5 Which mathematical concept is used in this problem? (a) Trigonometry (b) Triangle (c) Circle (d) MensurationIn this problem, Trigonometry is used So, the correct answer is (A)