Question 2 (ii) - sin 90 - θ, cos 90 - θ formula - Chapter 8 Class 10 Introduction to Trignometry

Last updated at August 14, 2026 by

Ex 8.3, 2 - Chapter 8 Class 10 Introduction to Trignometry - Part 2

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Question 2 Show that : (ii) cos 38 cos 52 sin 38 sin 52 = 0 Taking L.H.S cos 38 cos 52 sin 38 sin 52 = cos (90 52) cos (90 38) sin 38 sin 52 = sin 52 sin 38 sin 38 sin 52 = 0 = R.H.S L.H.S = R.H.S Hence proved

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