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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Example 3 The sides of a triangular plot are in the ratio of 3 : 5 : 7 and its perimeter is 300 m. Find its area. Area of triangle = √(s(s−a)(s−b)(s −c)) Here, s is the semi-perimeter, and a, b, c are the sides of the triangle Given Perimeter = 300 m Semi-Perimeter = s =Perimeter/2 s = 300/2 s = 150 m Given Ratio of sides is 3 : 5 : 7 Let sides be a = 3x meters , b = 5x meters , c = 7x meters where x is any number Now, Perimeter = 300 m a + b + c = 300 3x + 5x + 7x = 300 15x = 300 x = 300/15 x = 20 So, a = 3x meter b = 5x m c = 7x m Area of triangle = √(𝑠(𝑠 −𝑎)(𝑠 −𝑏)(𝑠 −𝑐)) Putting a = 60 m , b = 100 m, c = 140 m & s = 150 m Area = √(150(150−60)(150−100)(150−140)) m2 = √(150×90×50×10) m2 = √( (15×9×5)×(10)4) = √(15×(3×3)×5×(10)4) = √(15×(3×5)×3×(10)4) = √(15×15×3×(10)4) = √((15)2×3×(10)4) = √((15)2)×√3× √104 = (15) ×√3× 〖(104)〗^(1/2) = (15)×√3 × (102) = (15)×√3 × (100) = 1500√3 Thus, Area = 1500√3 m2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.