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Ex 10.1, 2 The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122m, 22m, and 120m. The advertisements yield an earning of Rs 5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay? Area of triangle = √(𝑠(𝑠 −𝑎)(𝑠 −𝑏)(𝑠 −𝑐)) Putting a = 122 m, b = 22 m , c = 120 m , s = 122 m Area = √(132(132−122)(132−22)(132−120)) m2 = √(132×(10)×(110)×(12) )m2 = √(132×11×12×(102) )m2 = √((132×132)×(102) )m2 = √((132)2×(102) )m2 = √((132)2) √((102) ) m2 = 〖(1322)〗^(1/2) × 〖(102)〗^(1/2) = 132 × 10 Rent of 1 m2 area per year = Rs 5000 Rent of 1 m2 area per month = Rs 5000/12 Rent of 1 m2 area per 3month = Rs 5000/12 ×3 Rent of 1320 m2 area for 3 months = Rs (5000 × 330) Therefore, the company had to pay Rs 1650000.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.