Question

A Mathematics Exhibition is being conducted in your School and one of your friends is making a model of a factor tree. He has some difficulty and asks for your help in completing a quiz for the audience. Observe the following factor tree and answer the following:

A Mathematics Exhibition is being conducted - Teachoo.jpg

part 2 - Question 3 - Case Based Questions (MCQ) - Serial order wise - Chapter 1 Class 10 Real Numbers

Question 1

What will be the value of x?
(a) 15005   (b) 13915  (c) 56920  (d) 17429

part 3 - Question 3 - Case Based Questions (MCQ) - Serial order wise - Chapter 1 Class 10 Real Numbers

Question 2

What will be the value of y?
(a) 23  (b) 22  (c) 11  (d) 19

part 4 - Question 3 - Case Based Questions (MCQ) - Serial order wise - Chapter 1 Class 10 Real Numbers

Question 3

What will be the value of z?
(a) 22  (b) 23  (c) 17  (d) 19

part 5 - Question 3 - Case Based Questions (MCQ) - Serial order wise - Chapter 1 Class 10 Real Numbers

Question 4

According to Fundamental Theorem of Arithmetic 13915 is a
(a) Composite number  
(b) Prime number  
(c) Neither prime nor composite  
(d) Even number

part 6 - Question 3 - Case Based Questions (MCQ) - Serial order wise - Chapter 1 Class 10 Real Numbers

Question 5

The prime factorisation of 13915 is
(a) 5 × 11 3   × 13 2  
(b) 5 × 11 3 × 23 2  
(c) 5 × 11 2 × 23 
(d) 5 × 11 2 × 13 2

part 7 - Question 3 - Case Based Questions (MCQ) - Serial order wise - Chapter 1 Class 10 Real Numbers

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Transcript

Question A Mathematics Exhibition is being conducted in your School and one of your friends is making a model of a factor tree. He has some difficulty and asks for your help in completing a quiz for the audience. Observe the following factor tree and answer the following:Question 1 What will be the value of x? (a) 15005 (b) 13915 (c) 56920 (d) 17429Here, x = 5 × 2783 = 13915 So, correct answer is (B) Question 2 What will be the value of y? (a) 23 (b) 22 (c) 11 (d) 19 Here, 2783 = 253 × y 2783/253 = y y = 2783/253 y = 11 So, correct answer is (C) Question 3 What will be the value of z? (a) 22 (b) 23 (c) 17 (d) 19 Here, 253 = 11 × z 253/11 = z z = 253/11 z = 23 So, correct answer is (B) Question 4 According to Fundamental Theorem of Arithmetic 13915 is a (a) Composite number (b) Prime number (c) Neither prime nor composite (d) Even number Here, 13915 = 5 × 2783 Since 13915 has factors other than 1 and the number itself ∴ It is a composite number So, correct answer is (A) Question 5 The prime factorisation of 13915 is (a) 5 × 11^3 × 13^2 (b) 5 ×〖 11〗^3 × 23^2 (c) 5 × 11^2 × 23 (d) 5 × 11^2 × 13^2 By Factor Tree, 13915 = 5 × 2783 = 5 × 253 × 11 = 5 × 11 × 23 × 11 = 5 × 112 × 23 So, correct answer is (C)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo