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Write the balanced equation for the following chemical reactions.
(ii) Barium chloride + Aluminium sulphate → Barium sulphate + Aluminium chloride
Answer
(ii) Barium chloride + Aluminium sulphate → Barium sulphate + Aluminium chloride
The skeletal chemical equation of the above reaction is
BaCl 2 + Al 2 (SO 4 ) 3 → BaSO 4 + AlCl 3
|
Element Name |
No of Atoms in Reactant |
No of Atoms in Product |
|
Barium |
1 |
1 |
|
Chlorine |
2 |
3 |
|
Aluminium |
2 |
1 |
|
Sulphur |
3 |
1 |
|
Oxygen |
12 |
4 |
-
Number of atoms of Oxygen in reactants
≠
number of atoms of Oxygen in products
To balance number of Oxygen,
We multiply the BaSO 4 in product by 3 (Oxygen is present in BaSO4)
The chemical equation becomes
BaCl 2 + Al 2 (SO 4 ) 3 → 3 BaSO 4 + AlCl 3
Now,
|
Element name |
No. of atoms in reactants |
No. of atoms in products |
|
Barium |
1 |
3 |
|
Chlorine |
2 |
3 |
|
Aluminium |
2 |
1 |
|
Sulphur |
3 |
3 |
|
Oxygen |
12 |
12 |
-
Now,
Number of atoms of Sulphur in reactants = number of atoms of Sulphur in products
Number of atoms of Oxygen in reactants = number of atoms of Oxygen in products
But, Number of other atoms in reactants ≠ number of other atoms in products
To balance, number of Aluminium,
We multiply AlCl 3 in product by 2 (as it contains Al)
The chemical equation becomes
BaCl 2 + Al 2 (SO 4 ) 3 → 3 BaSO 4 + 2 AlCl 3
Now,
|
Element name |
No. of atoms in reactants |
No. of atoms in product |
|
Barium |
1 |
3 |
|
Chlorine |
2 |
6 |
|
Aluminium |
2 |
2 |
|
Sulphur |
3 |
3 |
|
Oxygen |
12 |
12 |
-
Now,
Number of atoms of Barium in reactants ≠ number of atoms of Barium in products
Number of atoms of Chlorine in reactants ≠ number of atoms of Chlorine in products
To balance,
We multiply BaCl 2 in reactant by 3
The chemical equation becomes
3 BaCl 2 + Al 2 (SO 4 ) 3 → 3 BaSO 4 + 2 AlCl 3
|
Name of the element |
No. of atoms in Reactant |
No. of atoms in Product |
|
Barium |
3 |
3 |
|
Chlorine |
6 |
6 |
|
Aluminium |
2 |
2 |
|
Sulphur |
3 |
3 |
|
Oxygen |
12 |
12 |
Now, all the elements are balanced and the balanced equation is
3 BaCl 2 + Al 2 (SO 4 ) 3 → 3 BaSO 4 + 2 AlCl 3
3 BaCl 2 + Al 2 (SO 4 ) 3 → 3 BaSO 4 + 2 AlCl 3
