If x + y + z = 0, show that x^3 + y^3 + z^3 = 3xyz (with Video) - Ex 2.4

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Ex 2.4, 13 If x + y + z = 0, show that x3 + y3 + z3 = 3xyz . We know that x3 + y3 + z3 3xyz = (x + y + z) (x2 + y2 + z2 xy yz zx) Putting x + y + z = 0, x3 + y3 + z3 3xyz = (0) (x2 + y2 + z2 xy yz zx) x3 + y3 + z3 3xyz = 0 x3 + y3 + z3 = 3xyz Hence proved

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