Last updated at Dec. 8, 2016 by Teachoo

Transcript

Example 14 Factorize y2 – 5y + 6 by using the Factor Theorem. Step 1: We check if y2 is multiplied by 1. y2 – 5y + 6. Step 2: Writing y2 – 5y + 6.= (y – a) (y – b) So, ab = Constant term = 6 We find factors of 6 6 = 6 × 1 6 = 3 × 2 So, factors of 6 are 1, 2 and 3. We take value of y as 1 , 2, 3, –1, –2, –3, and check value of y2 – 5y + 6. Hence, a = 2 , b = 3 Now, y2 – 5y + 6.= (y – a) (y – b) = (y – 2) (y – 3)

Chapter 2 Class 9 Polynomials

Concept wise

- Definition
- Degree & Coefficient of a polynomial
- Value of a polynomial at a given point
- Verifying Zeroes of a polynomial
- Finding Zeroes of a polynomial
- Remainder Theoram
- Check if factor
- Factorisation by middle term
- Factorisation by factor formula
- Factorizing cubic equation
- Identity I - IV
- Identity V
- Identity VI & VII
- Identity VIII

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.