## How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?

Last updated at Aug. 6, 2019 by Teachoo

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NCERT Question 10 How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Current = I = 5 A Potential difference = V = 220 V Resistance of each resistor = R = 176 Ω We need to equivalent resistance such that current of 5 A flows When potential difference of 220 V is applied By ohm’s law, V = I R ∴ I = 𝑉/𝑅 R = 𝑉/𝐼 R = 220/5 R = 44 Ω Hence, equivalent resistance = 44 Ω Now, each resistor of 176 Ω is connected in parallel. We know that, In parallel combination equivalent resistance is given by 1/𝑅 = 1/𝑅_1 + 1/𝑅_2 + 1/𝑅_3 + … … Suppose n such resistors are joined 1/44 = 1/176 + 1/176 + 1/176 + … … n (times) 1/44 = n × 1/176 176/44 = n n = 176/44 n = 44/11 n = 4 ∴ 4 resistors of 176 Ω are joined parallel.

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Class 10

Chapter 12 Class 10 - Electricity

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.