An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.

Get live Maths 1-on-1 Classs - Class 6 to 12
Questions from Inside the chapter
Question 2 Page 200 Important
Question 3 Page 200 Important
Question 1 Page 202
Question 2 Page 202 Important
Question 3 Page 202 Important
Question 1 Page 209 Important
Question 2 Page 209 Important
Question 3 Page 209 Important
Question 4 Page 209
Question 5 Page 209 Important
Question 1 Page 213
Question 2 Page 213 Important
Question 1 Page 216
Question 2 Page 216 Important
Question 3 Page 216 Important
Question 4 Page 216 Important
Question 5 Page 216 Important
Question 1 Page 218 Important
Question 2 Page 218 Important
Question 3 Page 218 Important You are here
Question 1 Page 220 Important
Question 2 Page 220
Questions from Inside the chapter
Last updated at March 30, 2023 by Teachoo
Get live Maths 1-on-1 Classs - Class 6 to 12
Question 3 Page 218 An electric iron of resistance 20 takes a current of 5 A. Calculate the heat developed in 30 s. Resistance = R = 20 Ω Current = I = 5A Time taken = t = 30 s We know that, Heat generated is given by H = I2 R t H = (5)2 × 20 × 30 H = 25 × 20 × 30 H = 25 × 600 H = 15000 H = 15 × 103 H = 1.5 × 10 × 103 H = 1.5 × 104 J Heat generated is 1.5 × 104 J