Question 3 Page 218 - Chapter 12 Class 10 - Electricity

Last updated at August 14, 2026 by

An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.

Q3 Page 218 - An electric iron of resistance 20 takes a current of 5 A - Questions from Inside the chapter

part 2 - Question 3 Page 218 - Questions from Inside the chapter - Chapter 12 Class 10 - Electricity - Class 10

Remove Ads
Teachoo · Class 10 Explore Class 10

Transcript

Question 3 Page 218 An electric iron of resistance 20 takes a current of 5 A. Calculate the heat developed in 30 s. Resistance = R = 20 Ω Current = I = 5A Time taken = t = 30 s We know that, Heat generated is given by H = I2 R t H = (5)2 × 20 × 30 H = 25 × 20 × 30 H = 25 × 600 H = 15000 H = 15 × 103 H = 1.5 × 10 × 103 H = 1.5 × 104 J Heat generated is 1.5 × 104 J

Maninder Singh's photo - Co-founder, Teachoo

Made by

Maninder Singh

CA Maninder Singh is a Chartered Accountant with 16+ years of practical experience and 20+ years of teaching experience. He teaches Science, Economics, Accounting and English at Teachoo using clear explanations and exam-focused methods students can trust.

For faster and distraction-free study, students can choose Teachoo Black.