Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Case 1
Resistance = R
Potential Difference = V
Case 2
Resistance = R
Potential Difference = π/2
By Ohmβs law,
V = I R
π/π = I
β΄ I = π/π
Current in Case 1
I1 = π/π
Current in Case 2
I2 = π/2 Γ 1/π
= π/2π
Now,
πΌ_1/πΌ_2 = (π/π )/(π/2π )
πΌ_1/πΌ_2 = π/π Γ 2π /π
πΌ_1/πΌ_2 = 2
1/2 πΌ_1 = πΌ_2
πΌ_2 = 1/2 πΌ_1
β΄ When voltage becomes half, current also becomes half.
CA Maninder Singh is a Chartered Accountant for the past 13 years and a teacher from the past 17 years. He teaches Science, Economics, Accounting and English at Teachoo
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