Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?
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Last updated at April 16, 2024 by Teachoo
Case 1 Resistance = R Potential Difference = V Case 2 Resistance = R Potential Difference = π/2 By Ohmβs law, V = I R π/π = I β΄ I = π/π Current in Case 1 I1 = π/π Current in Case 2 I2 = π/2 Γ 1/π = π/2π Now, πΌ_1/πΌ_2 = (π/π )/(π/2π ) πΌ_1/πΌ_2 = π/π Γ 2π /π πΌ_1/πΌ_2 = 2 1/2 πΌ_1 = πΌ_2 πΌ_2 = 1/2 πΌ_1 β΄ When voltage becomes half, current also becomes half.