Questions from Inside the chapter

Class 10
Chapter 12 Class 10 - Electricity

## Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?

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### Transcript

Case 1 Resistance = R Potential Difference = V Case 2 Resistance = R Potential Difference = π/2 By Ohmβs law, V = I R π/π = I β΄ I = π/π Current in Case 1 I1 = π/π Current in Case 2 I2 = π/2 Γ 1/π = π/2π Now, πΌ_1/πΌ_2 = (π/π)/(π/2π) πΌ_1/πΌ_2 = π/π Γ 2π/π πΌ_1/πΌ_2 = 2 1/2 πΌ_1 = πΌ_2 πΌ_2 = 1/2 πΌ_1 β΄ When voltage becomes half, current also becomes half.

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#### Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 13 years and a teacher from the past 17 years. He teaches Science, Economics, Accounting and English at Teachoo