## Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?

Last updated at Aug. 5, 2019 by Teachoo

Transcript

Case 1 Resistance = R Potential Difference = V Case 2 Resistance = R Potential Difference = π/2 By Ohmβs law, V = I R π/π = I β΄ I = π/π Current in Case 1 I1 = π/π Current in Case 2 I2 = π/2 Γ 1/π = π/2π Now, πΌ_1/πΌ_2 = (π/π )/(π/2π ) πΌ_1/πΌ_2 = π/π Γ 2π /π πΌ_1/πΌ_2 = 2 1/2 πΌ_1 = πΌ_2 πΌ_2 = 1/2 πΌ_1 β΄ When voltage becomes half, current also becomes half.

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Class 10

Chapter 12 Class 10 - Electricity

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.