Graphical Representation Volt and Amperes

Experiment to Verify Ohm's Law

We take a conductor (Example Nichrome Wire)

We connect it to a circuit containing Voltmeter and Ammeter

When we supply current, we measure reading of Potential Difference with the help of Voltmeter and Electric Current with help of Ammeter

We calculate Ratio of Potential Difference/Electric Current

Now,we increase amount of current,

We again measure reading of Potential Difference and Electric Current and again Calculate Ratio

We note that Ratio Remains the Same

Hence Ohm's Law, which states that Ratio of Potential Difference and Electric Current Remains the same, is verified

 

Q1. The values of Current (I) flowing through a conductor for the corresponding values of potential difference (V) are given. Plot a graph between V and I.

V (Volt) 2.5 5 10 15 25
I (Ampere) 0.1 0.2 0.4 0.6 1

volts Amperes - teachoo.jpg

From the above table

We can see that,

the ratio of 𝑉/𝐼 is always constant.

This gives resistance

The resistance is 25 in above case

Graph volt and ameres Q 1 - teachoo.jpg

 

Q2. The values of Current (I) flowing through a conductor for the corresponding values of potential difference (V) are given. Plot a graph between V and I.

I (Ampere) 0.5 1 2 2.5 3
V (Volt) 2 4 8 10 12

volts Amperes -Q 2-  teachoo.jpg

From the above table

We can see that,

the ratio of V/I is always  constant.

This gives resistance

The resistance is 4 in above case

Graph volt and ameres Q 2 - teachoo.jpg

Q3. The values of Current (I) flowing through a conductor for the corresponding values of potential difference (V) are given. Plot a graph between V and I.
Hence. find the resistance.

 

I (Ampere) 0.5 1 2 3 4
V (Volt) 1.6 3.3 6.7 10.2 13.2

volts Amperes -Q 3-  teachoo.jpg

Slide24.JPG Slide25.JPG

  1. Class 10
  2. Chapter 12 Class 10 - Electricity

Transcript

From the above table We can see that, the ratio of 𝑉/𝐼 is nearly constant. To find resistance, we find the mean of the resistances found. R = (3.2 + 3. 3 + 3.35 + 3.4 + 3.3)/5 R = 16.55/5 R = 3.31 Ω

About the Author

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.