Teachoo Questions

Class 9
Chapter 11 Class 9 - Work and Energy

## Calculate the cost of using a 2kW immersion rod for heating water in a house for one hour each day for 60 days if the rate is Rs. 1.50 per unit kWh.

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Extra Questions 3 Calculate the cost of using a 2kW immersion rod for heating water in a house for one hour each day for 60 days if the rate is Rs. 1.50 per unit kWh. Power of the rod = 2 kW Time taken in 1 day = 1 hour Time taken in 60 days = 1 Γ 60 = 60 hours Letβs first find the energy consumed Power = (πΈπππππ¦ ππππ π’πππ)/(ππππ π‘ππππ) Energy consumed = Power Γ Time Energy consumed = 2 Γ 60 Energy consumed = 120 kWh Finding cost Cost of 1 kWh = Rs 1.50 Cost of 120 kWh = 120 Γ 1.50 = 120 Γ 150/100 = 12 Γ 15 = Rs 180 The total cost is Rs 180 Extra Questions 4 The power of a heart which beats 72 times in a minute is 1.2kW. Calculate the work done by heart for each beat. Power of the heart = 1.2 kW = 1.2 Γ 1000 W = 1200 W Time taken = 1 minute = 60 seconds We know that Power = (ππππ ππππ)/(ππππ π‘ππππ) Work done = Power Γ Time = 1200 Γ 60 = 72000 J Now, Work done to beat 72 times = 72000 J Work done to beat 1 times = 72000/72 = 1000 J = 1000/1000 kJ = 1 kJ Work done to produce 1 heart beat is 1 kJ