Example 8.4 - Chapter 8 Class 9 - Motion
Last updated at April 16, 2024 by Teachoo
Examples from NCERT Book
Last updated at April 16, 2024 by Teachoo
Example 8.4 Starting from a stationary position, Rahul paddles his bicycle to attain a velocity of 6 m sβ1 in 30 s. Then he applies brakes such that the velocity of the bicycle comes down to 4 m s-1 in the next 5 s. Calculate the acceleration of the bicycle in both the cases. Case 1 He starts from stationary position, and attains speed of 6 m/s in 30s Since he starts from stationary position Initial velocity = u = 0 m/s Final velocity = v = 6 m/s Time taken = t = 30 s Finding Acceleration Acceleration = (πΉππππ π£ππππππ‘π¦ β πΌπππ‘πππ π£ππππππ‘π¦)/ππππ = (π£ β π’)/π‘ = (6 β 0)/30 = 6/30 = 0.2 m/s2 Case 2 He applies brakes such that the velocity of the bicycle comes down to 4 m s-1 in the next 5 s Here, Final velocity in Case 1 becomes the initial velocity, Initial velocity = u = 6 m/s Final velocity = v = 4 m/s Time taken = 5 s Finding Acceleration Acceleration = (πΉππππ π£ππππππ‘π¦ β πΌπππ‘πππ π£ππππππ‘π¦)/ππππ = (π£ β π’)/π‘ = (4 β 6)/5 = (β2)/5 = β 0.4 m/s2 Therefore, Acceleration in Case 1 = 0.2 m/s2 Retardation in Case 2 = β0.4 m/s2