Finding the Unknown Class 7 (Ganita Prakash II)
Master Finding the Unknown Class 7 (Ganita Prakash II) with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.
NCERT Solutions
Finding the Unknown Class 7 (Ganita Prakash II) – NCERT Solutions
Each question below opens its complete step-by-step Teachoo solution.
Figure it out - Page 181
6 questionsQuestion 1
Write 5 equations whose solution is x = – 2.To do this, we start with 𝑥=−2 and do the same thing to both sides.
Here are 5 examples:
Question 2
Find the value of each unknown: (a) 2y = 60Solving
2y = 60
Taking 2 right side, so it becomes division
y = 60/2
y = 30
Question 2 Find the value of each unknown: (b) – 8 = 5x – 3Solving
–8 = 5x – 3
Since equation is equal, we take x term on right side
5x – 3 = –8
Taking –3 on right side, it becomes + 3
5x = –8 + 3
5x = – (8 – 3)
5x = – 5
Taking 5 right side, it becomes division
x = (−5)/5
x = –1
Question 2 Find the value of each unknown: (c) – 53w = –15Solving
–53w = –15
Taking –53 right side, so it becomes division
Note: –53 doesn’t become + 53, because it isn’t being added, since –53 is multiplied, it becomes division
w = (−15)/(−53)
w = 𝟏𝟓/𝟓𝟑
Question 2 Find the value of each unknown: (d) 13 – z = 8Solving
13 – z = 8
Putting 13 on left side, it becomes subtraction
–z = 8 – 13
–z = – 13 + 8
–z = – (13 – 8)
–z = – 5
We can cancel negative sign on both sides, or write –z = –1 × z
–1 × z = –5
z = (−5)/(−1)
z = 5
Question 2 Find the value of each unknown: (e) k + 8 = 12 – kSolving
k + 8 = 12 – k
Taking 8 on left side, it becomes subtraction
k = 12 – k – 8
k = (12 – 8) – k
k = 4 – k
Taking –k from right side to left side, it becomes + k
k + k = 4
2k = 4
k = 4/2
k = 2
Question 2 Find the value of each unknown: (f) 7m = m – 3Solving
7m = m – 3
Taking m from right side to left side, it becomes –m
7m – m = –3
6m = –3
Taking 6 to left side, it becomes division
m = (−3)/6
m = (−𝟏)/𝟐
Question 2 Find the value of each unknown: (g) 3n = 10 + nSolving
3n = 10 + n
Taking n from right side to left side, it becomes –n
3n – n = 10
2n = 10
Taking 2 to left side, it becomes division
n = 10/2
n = 5
Question 3
I am a 3-digit number. My hundred’s digit is 3 less than my ten’s digit. My ten’s digit is 3 less than my unit’s digit. The sum of all the three digits is 15. Who am I?A 3 digit number is like
View solutionQuestion 4
The weight of a brick is 1 kg more than half its weight. What is the weight of the brick?Let Weight of brick = W kg
View solutionQuestion 5
One quarter of a number increased by 9 gives the same number. What is the number?Let Number be x
View solutionQuestion 6
Given 4k + 1 = 13, find the values of: (a) 8k + 2 (b) 4k (c) k (d) 4k – 1 (e) – k – 2 Since we eventually need to find the value of k,
We do that first
Figure it out - Page 185 to 189
21 questionsQuestion 1
Fill in the blanks with integers. (a) 5 × ___ – 8 = 37We write the equation as
5x – 8 = 37
Putting 8 on right side, it becomes addition
5x = 37 + 8
5x = 45
Putting 5 on right side, it becomes division
x = 45/5
x = 9
Question 2
Ranju is a daily wage labourer. She earns ₹ 750 a day. Her employer pays her in 50 and 100 rupee notes. If Ranju gets an equal number of 50 and 100 rupee notes, how many notes of each does she have?Let Number of 50 and 100 rupee notes be x
View solutionQuestion 3
In the given picture, each black blob hides an equal number of blue dots. If there are 25 dots in total, how many dots are covered by one blob? Write an equation to describe this problem.Given that 3 black blobs cover blue dots. There are 25 dots total.
Each blob hides the same number of dots.
Question 4 (a)
Here are machines that take an input, perform an operation on it and send out the result as an output. Find the inputs in the following cases:First equation
View solutionQuestion 4 (b)
Here are machines that take an input, perform an operation on it and send out the result as an output. Find the inputs in the following cases:We assume Input = x
If we follow our machine
Input gets multipled by 3, so 3 × x = 3x
Input gets added by 3, so x + 3
Both these values are subtracted:
3x – (x + 3) = 3x – x – 3 = 2x – 3
Question 5
What are the inputs to these machines?
We solve both equations one-by-one
First equation
Question 6
A taxi driver charges a fixed fee of ₹800 per day plus ₹20 for each kilometer traveled. If the total cost for a taxi ride is ₹2200, determine the number of kilometres traveled.Let Number of kilometers travelled = k
View solutionQuestion 7
The sum of two numbers is 76. One number is three times the other number. What are the numbers?Let Smaller number = x
View solutionQuestion 8
The figure shows the diagram for a window with a grill. What is the gap between two rods in the grill?Let Gap between two rods = x cm
View solutionQuestion 9
In a restaurant, a fruit juice costs ₹15 less than a chocolate milkshake. If 4 fruit juices and 7 chocolate milkshakes cost ₹600, find the cost of the fruit juice and milkshake.Let Cost of chocolate milkshake = ₹ x
View solutionQuestion 10
Given 28p – 36 = 98, find the value of 14p – 19 and 28p – 38.We can solve this the "smart way" by looking for patterns instead of just finding 𝑝. Now, we are
Given 28p
And we have to find 14p and 28p
So, we can find 28p,
and then for 14p, we can do 14p = 𝟐𝟖𝒑/𝟐
Question 11
The steps to solve three equations are shown below. Identify and correct any mistakes.Mistake
In the first step, the student divided the 6x and 66 by 6, but forgot to divide the 9 by 6.
You cannot split the addition like that!
Question 12
Find the measures of the angles of these triangles.Let’s do this one by one
View solutionQuestion 13
Write 4 equations whose solution is u = 6.To do this, we start with u = 6 and do the same thing to both sides.
Here are 5 examples:
Question 14
The Bakhśhāli Manuscript (300 CE) mentions the following problem. The amount given to the first person is not known. The second person is given twice as much as the first. The third person is given thrice as much as the second; and the fourth person four times as much as the third. The total amount distributed is 132. What is the amount given to the first person? Let Amount given to 1st person = x
View solutionQuestion 15
The height of a giraffe is two and a half metres more than half its height. How tall is the giraffe?Let Height of giraffe = h m
View solutionQuestion 16
Two separate figures are given below. Each figure shows the first few positions in a sequence of arrangements made with sticks. Identify the pattern and answer the following questions for each figure: (a) How many squares are in position number 11 of the sequence? (b) How many sticks are needed to make the arrangement in position number 11 of the sequence? (c) Can an arrangement in this sequence be made using exactly 85 sticks? If yes, which position number will it correspond to? (d) Can an arrangement in this sequence be made using exactly 150 sticks? If yes, which position number will it correspond to?We do this one-by-one
First, we identify the pattern and then answer the questions
Also, in pattern we need to find number of squares and number of sticks
Question 17
A number increased by 36 is equal to ten times itself. What is the number?Let Number be x
View solutionQuestion 18
Solve these equations: (a) 5(r + 2) = 10Solving
5(r + 2) = 10
5 × r + 5 × 2 = 10
5r + 10 = 10
Putting 10 on right side, so it becomes –10
5r = 10 – 10
5r = 0
Putting 5 on right side, so it becomes division
r = 0/5
r = 0
Question 18 Solve these equations: (b) – 3(u + 2) = 2(u – 1)Solving
– 3(u + 2) = 2(u – 1)
Opening bracket
–3 × u + (–3) × 2 = 2 × u – 2 × 1
–3u – 6 = 2u – 2
Putting –6 on right side, so it becomes +6
–3u = 2u – 2 + 6
–3u = 2u + 6 – 2
–3u = 2u + 4
Putting 2u on left side, so it becomes –2u
–3u – 2u = 4
–u × (3 + 2) = 4
–u × 5 = 4
u × –5 = 4
Putting –5 on right side, so it becomes division
Note: –5 doen’t become +5 on right side, since it is dividing
u = 4/(−5)
u = (−𝟒)/𝟓
Question 18 Solve these equations: (c) 2(7 – 2n) = – 6Solving
2(7 – 2n) = –6
Opening bracket
2 × 7 – 2 × 2n = –6
14 – 4n = –6
Putting 14 on right side, so it becomes –14
–4n = –6 – 14
–4n = – (6 + 14)
–4n = –20
Putting –4 on right side, so it becomes division
Note: –4 doen’t become +4 on right side, since it is dividing
n = (−𝟐𝟎)/(−𝟒)
n = 20/4
n = 5
Question 19
Solve the equations to find a path from Start to the End. Show your work in the given boxes provided and colour your path as you proceed.
View solutionQuestion 20
There are some children and donkeys on a beach. Together they have 28 heads and 80 feet. How many donkeys are there? How many children are there? Let Number of children = c
Number of donkey = d
Why Learn This With Teachoo?
Finding the Unknown is Chapter 7 of NCERT Class 7 Ganita Prakash Part 2. It introduces linear equations through balances, unknown weights, matchstick patterns and everyday problems. Students learn to translate relationships into equations, solve them while preserving equality, check solutions and identify errors. Teachoo presents the concepts in a logical progression and provides step-by-step help for the chapter’s Figure it out questions.
What is an equation?
An equation states that two mathematical expressions have the same value. It may contain an unknown represented by a letter. Solving the equation means finding the value of that letter that makes the equality true.
Unknown Weights uses a balance model. If equal quantities are added to, removed from, multiplied on or divided on both sides of a balanced scale, balance is preserved. This is the central principle of equation solving: perform the same valid operation on both sides.
Matchstick patterns connect equations with generalisation. Students describe how the number of sticks changes with the number of figures and use a letter for an unknown stage or quantity. This builds on the letter-number expressions learned in Part 1.
The chapter moves from forming simple equations to solving them and applying them in word problems. Generating Equations reverses the usual process: students construct an equation that satisfies a condition or represents a story. This confirms that an equation is a model of a relationship, not merely a set of symbols to manipulate.
Mind the Mistake, Mend the Mistake examines invalid steps and helps students explain how to correct them. A Pinch of History places equation methods in mathematical context. The “Magic Formula” for Linear Equations summarises an efficient general method, but students are encouraged to understand its balance-based justification.
The Figure it out questions on pages 181 and 185–189 combine equations, patterns, error analysis and applications.
Topics covered on Teachoo
Students can study:
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introduction to unknowns and equations;
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unknown-weight balance problems;
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equations from matchstick patterns;
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solving linear equations;
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equation-based word problems;
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generating equations from conditions;
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identifying and repairing mistakes;
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historical context;
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the general method or “Magic Formula” for linear equations; and
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Figure it out solutions for pages 181 and 185–189.
Learning outcomes
Students should be able to define an unknown, translate a verbal or visual relationship into an equation and solve a one-variable linear equation using equality-preserving operations. They should generate equations from patterns, check a solution by substitution and explain why an incorrect step fails. In applications, they should interpret the numerical solution in context and reject values that do not satisfy the original conditions.
Why is Finding the Unknown important?
Equations are one of the main tools of mathematics. They describe relationships in geometry, science, finance, data and everyday decision-making. The chapter establishes the habits needed for later algebra: defining a variable, preserving equality, simplifying accurately and checking a proposed solution.
It also demonstrates the difference between an expression and an equation. An expression represents a value, while an equation compares two expressions and asks when they are equal.
How Teachoo helps you learn
Teachoo’s sequence moves from visual balance models to symbolic equations and applications. Worked answers show each operation on both sides, making the equality-preserving logic visible. Students can use the solutions to diagnose exactly where a sign, operation or translation error occurred.
For every word problem, first define the unknown in words. Translate each relationship carefully and form the equation before solving. Simplify one step at a time, performing the same operation on both sides. Substitute the result into the original equation and verify that the left-hand side equals the right-hand side.
For pattern questions, draw small stages and determine which quantity is fixed and which changes. An equation can then be used either to predict a stage or to find the stage associated with a given total.
Common mistakes to avoid
Do not move a term across the equals sign and change its sign as an unexplained trick. The shorthand represents performing inverse operations on both sides; understanding this prevents errors. Distribute multiplication over every term inside brackets and keep negative signs attached to their terms.
Do not stop after finding a numerical value. Check it in the original equation and state the answer in the problem’s context. If the result is impossible for the context, review the equation formation.
Deeper reasoning and concept connections
In Finding the Unknown (Ganita Prakash Part 2), fluency means more than repeating a procedure. Students should be able to recognise the underlying structure when the numbers, diagram, wording or orientation changes. A useful routine is: identify the mathematical objects, list the known and unknown quantities, state the governing property, carry out the steps and verify that every condition has been used.
Look for connections within the chapter as well. A definition usually leads to a representation; the representation reveals a pattern; and the pattern supports a rule or calculation. Explaining this chain improves retention and helps with case-based questions. It also prevents the common mistake of selecting a formula simply because its symbols resemble the numbers in the question.
How to solve unfamiliar and competency-based questions
Use a five-step response: interpret, represent, select, solve and verify. Interpret the wording; represent the information; select a definition, property or formula; solve without skipping the logical step; and verify through substitution, estimation, measurement or an alternative representation. This routine works for direct exercises as well as case-based questions.
If information appears unnecessary, ask whether it establishes a hidden condition. If information is missing, state what cannot be determined instead of inventing a value. In written answers, name the rule being used. Clear reasoning helps a teacher award method marks and also makes the page easier for a student—or an AI answer system—to retrieve for the precise doubt being asked.
What complete mastery looks like
For Finding the Unknown (Ganita Prakash Part 2), a student should be able to define the central ideas in simple language, recognise them in different representations, solve routine questions accurately and explain the method used. They should also be able to correct a flawed solution, create an example satisfying given conditions and combine two ideas from the chapter in one problem. A reliable mastery test is to solve one direct question, one application question and one reasoning question without looking at notes, then explain all three aloud or in writing.
Keep a compact error log with four labels: concept, interpretation, calculation and presentation. Reattempt each error after a gap instead of rereading the answer immediately. Improvement comes from correcting the decision that caused the mistake, not from repeating questions whose method is already known.
Additional frequently asked questions
What should a student know before starting Finding the Unknown (Ganita Prakash Part 2)?
Revise the definitions, number operations, diagrams or notation used at the beginning of the chapter. The prerequisite list should be short: if an earlier skill blocks progress, repair that skill with two or three focused questions and return to the chapter.
How can a student check an answer in Finding the Unknown (Ganita Prakash Part 2)?
Use an independent check whenever possible: substitute the result, reverse the operation, estimate its size, compare it with the figure, test a simpler case or solve using another representation. A check should examine the mathematical condition, not merely repeat the same arithmetic.
How many questions are enough for strong preparation?
There is no fixed number. Stop counting questions and track coverage: every concept, every standard method, at least one mixed problem, one competency-based problem and every previously incorrect type should be solved independently. Ten varied, analysed questions are more valuable than fifty copied solutions.
How should Teachoo solutions be used without becoming dependent on them?
Attempt the question first and mark the exact step where progress stops. Read only enough of the solution to repair that step, close it and restart the question. Finally, solve a similar problem without help. This turns a solution into feedback rather than a substitute for thinking.
Frequently asked questions
What does it mean to solve an equation?
It means finding the value of the unknown that makes both sides of the equation equal.
Why must the same operation be performed on both sides?
Because an equation represents equality. Applying the same valid operation to equal quantities preserves that equality.
How can I check a solution?
Substitute the value for the unknown in the original equation and calculate both sides. They should be equal.
Define the unknown, form the relationship, preserve the balance and verify the result. That four-step routine turns equation solving into understandable reasoning.