Question 1 - Pythagoras Theoram - Proving - Chapter 6 Class 10 Triangles

Last updated at July 15, 2026 by

Example 12 - If AD perpendicular BC, prove that AB2 + CD2 - Examples

Example 12 - Chapter 6 Class 10 Triangles - Part 2

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Question 4 In figure, if AD BC, prove that AB2 + CD2 = BD2 + AC2. Given: where AD BC To Prove:- AB2 + CD2 = BD2 + AC2 Proof: Since AC BD ADC = ADB = 90 Doing (1) (2) AB2 AC2 = (AD2 + BD2) (AD2 + CD2) AB2 AC2 = AD2 + BD2 AD2 CD2 AB2 AC2 = BD2 CD2 AB2 + CD2 = BD2 + AC2 Hence proved

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