This question was asked in Ex 7.4, 3
In fig.5.49. angle B < angle A and angle C < angle D. Show that AD < BC
Answers!
Given:- angle B<angle A and angle C< angle D
To prove :- AD < BC
Proof:- Now,
AO <Bo --(1) ( side opposite to larger angle is longest)
Also,
DO <CO --- (2)
Add (1) and (2)
AO DO< BO CO
=AD <BC
Comment
Answer the question...
Given:- angle B<angle A and angle C< angle D
To prove :- AD < BC
Proof:- Now,
AO <Bo --(1) ( side opposite to larger angle is longest)
Also,
DO <CO --- (2)
Add (1) and (2)
AO DO< BO CO
=AD <BC
To prove :- AD < BC
Proof:- Now,
AO <Bo --(1) ( side opposite to larger angle is longest)
Also,
DO <CO --- (2)
Add (1) and (2)
AO DO< BO CO
=AD <BC
Comment