Is that formula proper isn't it 1/2[x1(y2-y3) x2(y3-y1) x3(y1-y2)]
So I think solution may change . In this question they have taken formula as 1/2[x1(y2-y3) x2(y3-y1) x3(y1-y3)]
Go ad-free with Teachoo Black
Adblock detected
Skip every ad. Keep every answer.
Teachoo Black gives you a clean, uninterrupted study experience on every page.
Go ad-free →
A second ad-free Teachoo reminder
One last thing
This is what ad-free feels like.
No banners. No interruptions. Just the lesson.
Go ad-free →Please login to view more pages. It's free :)
Teachoo gives you a better experience when you're logged in. Please login :)