Answers!
Here,In 1st A.P
First term,a=4
Common difference,d = 3
In 2nd A.P
First Term,A=5
Common Difference,D = ?
According To Question
a↓12 = A↓8
a 11d = A 7D [a↓n = a (n-1)d]
Putting values,
4 11× 3 = 5 7D
=> -1 33/7 = D
Comment
I don't know how it goes??
Answer the question...
Here,In 1st A.P
First term,a=4
Common difference,d = 3
In 2nd A.P
First Term,A=5
Common Difference,D = ?
According To Question
a↓12 = A↓8
a 11d = A 7D [a↓n = a (n-1)d]
Putting values,
4 11× 3 = 5 7D
=> -1 33/7 = D
First term,a=4
Common difference,d = 3
In 2nd A.P
First Term,A=5
Common Difference,D = ?
According To Question
a↓12 = A↓8
a 11d = A 7D [a↓n = a (n-1)d]
Putting values,
4 11× 3 = 5 7D
=> -1 33/7 = D
Comment
I don't know how it goes??