Last updated at Dec. 16, 2024 by Teachoo
Example 12 Using Identity (II), find (i) (4πβ3π)^2 (4πβ3π)^2 (πβπ)^2=π^2+π^2β2ππ Putting π = 4π & π = 3π = (4π)^2+(3π)^2β2(4π)(3π) = (4^2Γπ^2 )+(3^2Γπ^2 )β(2Γ4Γ3)Γ(πΓπ) = πππ^π+ππ^πβππππ
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About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo