1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
  3. Ex 2.2
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Ex 2.2, 7 - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Ex 2.2, 7 Simplify and solve the following linear equations. 3 (t – 3) = 5 (2t + 1) 3 (t – 3) = 5 (2t + 1) 3t − 9 = 5 (2t + 1) 3t − 9 = 10t + 5 3t − 10t − 9 = 5 −7t − 9 = 5 −7t = 5 + 9 −7t = 14 t = 14/(−7) t = −2 Check:- ∴ LHS = RHS Hence Verified. R.H.S 5(2t + 1) = 5 (2(−2) + 1) = 5 (−4 + 1) = 5 (−3) = −15
  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise

    3. Ex 2.2

    Examples →
Examples →
Chapter 2 Class 8 Linear Equations in One Variable
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo