Last updated at Dec. 16, 2024 by Teachoo
Ex 2.2, 3 Solve the following linear equations. x + 7 โ 8๐ฅ/3=17/6โ5๐ฅ/2x + 7 โ 8๐ฅ/3=17/6โ5๐ฅ/2 (๐(๐ + ๐) โ ๐๐)/๐=(๐๐ โ ๐๐ ร ๐)/๐ (3๐ฅ + 21 โ 8๐ฅ)/3=(17 โ 15๐ฅ)/6 (3๐ฅ โ 8๐ฅ + 21)/3=(17 โ 15๐ฅ)/6 (โ5๐ฅ + 21)/3=(17 โ 15๐ฅ)/6 6 (โ5x + 21) = 3 (17 โ 15x) โ30x + 126 = 51 โ 45x โ30x = โ45x + 51 โ 126 โ30x = โ45x โ 75 โ30x + 45x = โ75 15x = โ 75 x = (โ75)/15 x = โ5 Check:- โด LHS = RHS Hence Verified. L.H.S ๐ฅ+7โ8๐ฅ/3 =โ5+7โ(8 (โ5))/3 =2+40/3 =(6 + 40)/3=46/3 R.H.S 17/6โ5๐ฅ/2 =17/6โ5(โ5)/2=17/6+25/2 =(17 +3(25))/6 =(17 + 75)/6=92/6=46/3
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo