Last updated at Dec. 16, 2024 by Teachoo
Ex 2.1, 8 Solve the following equations and check your results. 2๐ฅ/3+1=7๐ฅ/15+3 2๐ฅ/3+1=7๐ฅ/15+3 (๐๐ + ๐)/๐=(๐๐ + ๐ ร ๐๐)/๐๐ (2๐ฅ + 3)/3=(7๐ฅ + 45)/15 15 (2x + 3) = 3 (7x + 45) 30x + 45 = 3 (7x + 45) 30x + 45 = 21x + 135 30x โ 21x + 45 = 135 9x + 45 = 135 9x = 135 โ 45 9x = 90 x = 90/9 x = 10 Check:- โด LHS = RHS Hence Verified. L.H.S 2๐ฅ/3+1=(2 ร 10 + 1 )/3 = (20 + 3)/3=23/2 R.H.S (7๐ฅ )/15+3=(7 ร 10 )/15+3=14/3+3 = (14 + 9)/3=23/3
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo