Ex 4.1, 7 (i) - Chapter 4 Class 12 Determinants
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 4.1, 7 Find values of x, if (i) |■8(2&4@5&1)| = |■8(2x&4@6&x)| Now |■8(2&4@5&1)| = |■8(2x&4@6&x)| Putting values −18 = 2x2 – 24 2x2 – 24 = −18 2x2 = −18 + 24 2x2 = 6 Calculating |■8(2&4@5&1)| = 2(1) – 5(4) = 2 – 20 = – 18 Calculating |■8(2x&4@6&x)| = 2x(x) – 6 × 4 = 2x2 – 24 x2 = 6/2 x2 = 3 x = ± √𝟑 Hence, value of x is ± √3
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