Example 4 (i) - Chapter 12 Class 11 Limits and Derivatives
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example, 4 Evaluate: (i) limx→0 sin4xsin 2x limx→0 sin4xsin 2x = limx→0 sin 4x × limx→0 1 sin2𝑥 Multiplying & dividing by 4x = limx→0 sin 4x . 4𝑥4𝑥 × limx→0 1 sin2𝑥 = limx→0 sin4𝑥4𝑥 . 4x × limx→0 1 sin2𝑥 = 𝐥𝐢𝐦𝐱→𝟎 𝒔𝒊𝒏𝟒𝒙𝟒𝒙 × limx→0 4x × limx→0 1 sin2𝑥 = 1 × limx→0 4x × limx→0 1 sin2𝑥 = 1 × limx→0 4x × limx→0 1 sin2𝑥 = limx→0 1 sin2𝑥 . 4x Multiplying & dividing by 2x = limx→0 1sin 2x × 4x × 2𝑥2𝑥 = limx→0 2𝑥sin 2x × 4𝑥2𝑥 = limx→0 2𝑥 sin2𝑥 × 2 = 2 limx→0 2𝑥 sin2𝑥 = 2 ÷ 𝐥𝐢𝐦𝐱→𝟎 𝐬𝐢𝐧𝟐𝒙𝟐𝒙 = 2 ÷ 1 = 21 = 2
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Example 2 (iii) Important
Example 2 (iv)
Example 2 (v)
Example 3 (i) Important
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Example 4 (i) You are here
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Example 5
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Example 11
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Example 19 (ii)
Example 20 (i)
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Example 21 (i)
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Example 22 (i)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo