Example 2 - Chapter 10 Class 11 Conic Sections
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 2 Find the equation of the circle with centre (–3, 2) and radius 4. We know that equation of a circle is (x – h)2 + (y – k)2 = r2 Where (h, k) is the centre & r is the radius Here Centre (h, k) = (–3, 2) So h = −3 & k = 2 & radius (r) = 4. Putting values in (1) (x − (−3))2 + (y – 2)2 = (4)2 (x + 3)2 + (y – 2)2 = 16 (x2 + 32 + 6x) + (y2 + 22 − 4y) = 16 x2 + 9 + 6x + y2 + 4 – 4y = 16 x2 + y2 + 6x – 4y + 13 = 16 x2 + y2 + 6x – 4y + 13 − 16 = 0 x2 + y2 + 6x – 4y − 3 = 0 Hence required equation of circle is x2 + y2 + 6x – 4y − 3 = 0
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo