Check sibling questions


Transcript

Ex 10.3, 12 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (b) 70 cm and 36 cm. Here, Number of tiles = (๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘๐‘ก๐‘Ž๐‘›๐‘”๐‘ข๐‘™๐‘Ž๐‘Ÿ ๐‘Ÿ๐‘’๐‘”๐‘–๐‘œ๐‘›)/(๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘๐‘ก๐‘Ž๐‘›๐‘”๐‘ข๐‘™๐‘Ž๐‘Ÿ ๐‘ก๐‘–๐‘™๐‘’) From part (a), Area of rectangular tile = 60 cm2 Finding area of rectangular region Rectangular region Length of rectangle = 70 cm Breadth of rectangle = 36 cm Area of rectangle = Length ร— Breadth = 70 ร— 36 = 2520 sq. cm = 2520 ใ€–๐‘๐‘šใ€—^2 Now, Number of tiles = (๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘๐‘ก๐‘Ž๐‘›๐‘”๐‘ข๐‘™๐‘Ž๐‘Ÿ ๐‘Ÿ๐‘’๐‘”๐‘–๐‘œ๐‘›)/(๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘๐‘ก๐‘Ž๐‘›๐‘”๐‘ข๐‘™๐‘Ž๐‘Ÿ ๐‘ก๐‘–๐‘™๐‘’๐‘ ) = 2520/60 = 252/6 = 42 โˆด 42 tiles are required to cover the given region

  1. Chapter 10 Class 6 Mensuration
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo