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What is the value of (tan 𝜃 cosec 𝜃) 2   − (sin 𝜃  sec 𝜃)2

(a) −1   (b) 0   (c) 1   (d) 2


Transcript

Question 32 What is the value of (tan 𝜃 cosec 𝜃)2 − (sin 𝜃 sec 𝜃)2 (a) −1 (b) 0 (c) 1 (d) 2 (tan 𝜃 cosec 𝜃)2 − (sin 𝜃 sec 𝜃)2 = (sin⁡θ/cos⁡〖θ 〗 ×1/sin⁡〖θ 〗 )^2 − (sin⁡〖θ 〗×1/cos⁡〖θ 〗 )^2 = (1/cos⁡〖θ 〗 )^2 − (sin⁡〖θ 〗/cos⁡〖θ 〗 )^2 = 〖𝐬𝐞𝐜〗^𝟐 𝜽 −〖𝐭𝐚𝐧〗^𝟐 𝜽 = 1 So, the correct answer is (c) We know that 1 + tan2 θ = sec2 θ 1 = sec2 θ − tan2 θ sec2 θ − tan2 θ = 1

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About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo