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Example 14 Use the Identity (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ to find the following: (ii) 95 Γ— 103 95 Γ— 103 = (100βˆ’5)Γ—(100+3) = [100+(βˆ’5)]Γ—[100+3] (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ Putting π‘₯ = 100 , π‘Ž = βˆ’5 & 𝑏 = 3 = (100)^2+(βˆ’5+2)(100)+(βˆ’5)(3) = 10000+(βˆ’2Γ—100)+(βˆ’15) = 10000βˆ’200βˆ’15 = 1000βˆ’215 = πŸ—πŸ•πŸ–πŸ“

  1. Chapter 8 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo