Ex 14.4, 13 - Chapter 14 Class 8 Factorisation

Last updated at Dec. 26, 2018 by Teachoo

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Ex 14.4, 13 Find and correct the errors in the following mathematical statements. (2a + 3b) (a – b) = 2𝑎^2 – 3𝑏^2 (2a + 3b) (a – b) = 2𝑎^2 – 3𝑏^2 Solving L.H.S : (2a + 3b) (a – b) = 2a (a − b) + 3b (a − b) = (2a × a) − (2a × b) + (3b × a) − (3b × b) = 〖2𝑎〗^2 − 2ab + 3ba − 〖3𝑏〗^2 = 〖2𝑎〗^2 − 2ab + 3ab − 〖3𝑏〗^2 Taking ab common = 〖2𝑎〗^2 + ab (−2 + 3) − 〖3𝑏〗^2 (Since 3ba = 3ab) = 〖2𝑎〗^2 + ab − 〖3𝑏〗^2 ∴ (2a + 3b) (a − b) = 〖𝟐𝒂〗^𝟐 + ab − 〖𝟑𝒃〗^𝟐 is the correct statement

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.