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Last updated at Dec. 24, 2018 by Teachoo
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Ex 9.4, 3 Simplify. (iv) (๐+๐) (๐โ๐)+(๐โ๐) (๐+๐)+2 (๐๐+๐๐) Here, there are 3 expressions 1st expression = (๐+๐) (๐โ๐) 2nd expression = (๐โ๐) (๐+๐) 3rd expression = 2 (๐๐+๐๐) Solving 1st expression (๐+๐) (๐โ๐) = ๐(๐โ๐)+๐ (๐โ๐) = (๐ร๐)โ(๐ร๐)+(๐ร๐)โ(๐ร๐) = ๐๐โ๐๐+๐๐โ๐๐ Solving 2nd expression (๐โ๐) (๐+๐) = ๐(๐+๐)โ๐ (๐+๐) = (๐ร๐)+(๐ร๐)โ(๐ร๐)โ(๐โ๐) = ๐๐+๐๐โ๐๐โ๐๐ Solving 3rd expression 2 (๐๐+๐๐) = (2ร๐๐)+(2ร๐๐) = 2๐๐+2๐๐ Now, our expression becomes (๐+๐) (๐โ๐)+(๐โ๐) (๐+๐)+2 (๐๐+๐๐) = ๐๐โ๐๐+๐๐โ๐๐+๐๐+๐๐โ๐๐โ๐๐+2๐๐+2๐๐ = (๐๐+๐๐+2๐๐)+(โ๐๐+๐๐)+(๐๐โ๐๐)+(โ๐๐โ๐๐+2๐๐) = (1+1+2)๐๐+(โ1+1)๐๐+(1โ1)๐๐+(โ1โ1+2)๐๐ = 4๐๐+(0)๐๐+(0)๐๐+(0)๐๐ = ๐๐๐
Multiplication of Polynoimals by Polynomials
Multiplying Binomial by a Trinomial
Ex 9.4, 1 (i)
Ex 9.4, 1 (ii)
Ex 9.4, 1 (iv) Important
Ex 9.4, 1 (iii) Important
Ex 9.4, 2 (i)
Ex 9.4, 2 (ii)
Example 9 Important
Example 8
Ex 9.4, 2 (iii)
Ex 9.4, 2 (iv)
Ex 9.4, 1 (v) Important
Ex 9.4, 1 (vi) Important
Ex 9.4, 3 (iii)
Ex 9.4, 3 (i)
Ex 9.4, 3 (ii)
Ex 9.4, 3 (vi)
Ex 9.4, 3 (viii)
Example 10 Important
Ex 9.4, 3 (iv) Important You are here
Ex 9.4, 3 (v) Important
Ex 9.4, 3 (vii) Important
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