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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Concept wise

Transcript

Ex 9.4, 3 Simplify. (iv) (๐‘Ž+๐‘) (๐‘โˆ’๐‘‘)+(๐‘Žโˆ’๐‘) (๐‘+๐‘‘)+2 (๐‘Ž๐‘+๐‘๐‘‘) Here, there are 3 expressions 1st expression = (๐‘Ž+๐‘) (๐‘โˆ’๐‘‘) 2nd expression = (๐‘Žโˆ’๐‘) (๐‘+๐‘‘) 3rd expression = 2 (๐‘Ž๐‘+๐‘๐‘‘) Solving 1st expression (๐‘Ž+๐‘) (๐‘โˆ’๐‘‘) = ๐‘Ž(๐‘โˆ’๐‘‘)+๐‘ (๐‘โˆ’๐‘‘) = (๐‘Žร—๐‘)โˆ’(๐‘Žร—๐‘‘)+(๐‘ร—๐‘)โˆ’(๐‘ร—๐‘‘) = ๐‘Ž๐‘โˆ’๐‘Ž๐‘‘+๐‘๐‘โˆ’๐‘๐‘‘ Solving 2nd expression (๐‘Žโˆ’๐‘) (๐‘+๐‘‘) = ๐‘Ž(๐‘+๐‘‘)โˆ’๐‘ (๐‘+๐‘‘) = (๐‘Žร—๐‘)+(๐‘Žร—๐‘‘)โˆ’(๐‘ร—๐‘)โˆ’(๐‘โˆ’๐‘‘) = ๐‘Ž๐‘+๐‘Ž๐‘‘โˆ’๐‘๐‘โˆ’๐‘๐‘‘ Solving 3rd expression 2 (๐‘Ž๐‘+๐‘๐‘‘) = (2ร—๐‘Ž๐‘)+(2ร—๐‘๐‘‘) = 2๐‘Ž๐‘+2๐‘๐‘‘ Now, our expression becomes (๐‘Ž+๐‘) (๐‘โˆ’๐‘‘)+(๐‘Žโˆ’๐‘) (๐‘+๐‘‘)+2 (๐‘Ž๐‘+๐‘๐‘‘) = ๐‘Ž๐‘โˆ’๐‘Ž๐‘‘+๐‘๐‘โˆ’๐‘๐‘‘+๐‘Ž๐‘+๐‘Ž๐‘‘โˆ’๐‘๐‘โˆ’๐‘๐‘‘+2๐‘Ž๐‘+2๐‘๐‘‘ = (๐‘Ž๐‘+๐‘Ž๐‘+2๐‘Ž๐‘)+(โˆ’๐‘Ž๐‘‘+๐‘Ž๐‘‘)+(๐‘๐‘โˆ’๐‘๐‘)+(โˆ’๐‘๐‘‘โˆ’๐‘๐‘‘+2๐‘๐‘‘) = (1+1+2)๐‘Ž๐‘+(โˆ’1+1)๐‘Ž๐‘‘+(1โˆ’1)๐‘๐‘+(โˆ’1โˆ’1+2)๐‘๐‘‘ = 4๐‘Ž๐‘+(0)๐‘Ž๐‘‘+(0)๐‘๐‘+(0)๐‘๐‘‘ = ๐Ÿ’๐’‚๐’„

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.