

Last updated at Dec. 24, 2018 by Teachoo
Transcript
Example 13 Using Identity (III), find (i) (3/2 π+2/3 π)(3/2 πβ2/3 π) (3/2 π+2/3 π)(3/2 πβ2/3 π) (π+π)(πβπ)=π^2βπ^2 Putting π = 3/2 π & π = 2/3 π = (3/2 π)^2β(2/3 π)^2 = (3/2)^2Γπ^2β(2/3)^2Γπ^2 = π/π π^πβπ/π π^π Example 13 Using Identity (III), find (ii) γ983γ^2β γ17γ^2 γ983γ^2β γ17γ^2 π^2βπ^2=(π+π)(πβπ) Putting π = 983 & π = 17 = (983+17)Γ(983β17) = 1000Γ966 = 9,66,000 Example 13 Using Identity (III), find (iii) 194 Γ 206 194 Γ 206 = (200β6)Γ(200+6) 194 Γ 206 = (200β6)Γ(200+6) = (200)^2β(6)^2 = 40000β36 = 39964
Algebra Identities - Identity III
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