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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Concept wise

Transcript

Ex 9.4, 3 Simplify. (i) (๐‘ฅ^2โˆ’5) (๐‘ฅ+5)+25 Here, there are 2 expressions: 1st expression = (๐‘ฅ^2โˆ’5) (๐‘ฅ+5) 2nd expression = 25 Solving 1st expression (๐‘ฅ^2โˆ’5) (๐‘ฅ+5) = ๐‘ฅ^2 (๐‘ฅ+5)โˆ’5(๐‘ฅ+5) = (๐‘ฅ^2ร—๐‘ฅ)+(๐‘ฅ^2ร—5)โˆ’(โˆ’5ร—๐‘ฅ)โˆ’(5ร—5) = ๐‘ฅ^3+5๐‘ฅ^2โˆ’5๐‘ฅโˆ’25 Now, our expression is (๐‘ฅ^2โˆ’5) (๐‘ฅ+5)+25 = ๐‘ฅ^3+5๐‘ฅ^2โˆ’5๐‘ฅโˆ’25+25 = ๐’™^๐Ÿ‘+๐Ÿ“๐’™^๐Ÿโˆ’๐Ÿ“๐’™

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.