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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.4, 2 Find the product. (iii) (๐‘Ž^2+๐‘)(๐‘Ž+๐‘^2 ) (๐‘Ž^2+๐‘)(๐‘Ž+๐‘^2 ) = ๐‘Ž^2 (๐‘Ž+๐‘^2 )+๐‘(๐‘Ž+๐‘^2 ) = (๐‘Ž^2ร—๐‘Ž)+(๐‘Ž^2ร—๐‘^2 )+(๐‘ร—๐‘Ž)+(๐‘ร—๐‘^2 ) = ๐’‚^๐Ÿ‘+๐’‚^๐Ÿ ๐’ƒ^๐Ÿ+๐’ƒ๐’‚+๐’ƒ^๐Ÿ‘

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.